1 You should express y first y = x 3 / 2 Then y ′ = 3 2 x 1 / 2 and ∫ 0 5 / 9 1 y ′ 2 d x = ∫ 0 5 / 9 1 9 4 x d x = 8 27 ( 1 9 4 x) 3 / 2 x = 0 x = 5 / 9 = 19 27 ShareThe process of obtaining the equation is similar, but it is more algebraically intensive Given the focus (h,k) and the directrix y=mxb, the equation for a parabola is (y mx b)^2 / (m^2 1) = (x h)^2 (y k)^2 Equivalently, you could put it in general form x^2 2mxy m^2 y^2 2 h (m^2 1) mbx 2 k (m^2 1)^2 by (h^2 k^2So the equation for the line of symmetry is x = 3 In order to visualize the line of symmetry, take the picture of the parabola above and draw an imaginary vertical line through the vertex
Characteristics Of Parabolas College Algebra
