1 You should express y first y = x 3 / 2 Then y ′ = 3 2 x 1 / 2 and ∫ 0 5 / 9 1 y ′ 2 d x = ∫ 0 5 / 9 1 9 4 x d x = 8 27 ( 1 9 4 x) 3 / 2 x = 0 x = 5 / 9 = 19 27 ShareThe process of obtaining the equation is similar, but it is more algebraically intensive Given the focus (h,k) and the directrix y=mxb, the equation for a parabola is (y mx b)^2 / (m^2 1) = (x h)^2 (y k)^2 Equivalently, you could put it in general form x^2 2mxy m^2 y^2 2 h (m^2 1) mbx 2 k (m^2 1)^2 by (h^2 k^2So the equation for the line of symmetry is x = 3 In order to visualize the line of symmetry, take the picture of the parabola above and draw an imaginary vertical line through the vertex
Characteristics Of Parabolas College Algebra
Vertex of parabola y=2(x-3)^2+4